If one two one
plus two one two
is three times forty-three
Then what can one
one one plus one
one one plus
one one be?

...wow...

Yeah I bet you can't solve it, fuckin brick

looked at literally, you just said

if 121 plus 212 is 129, what can 111 plus 111 plus 11 be?

*confused* lol

Its about the same amount of times i have been wankin


























*calculator explodes*

roflmao ^

^^ u know matt germain?

I'm thinking 118

wow a riddle... calculations is wrong so its an error sum :P

how'd you get 118?

i tried adding the 2 equations - (121 plus 212) and (111 plus 111 plus 11) and then divided the first sum by 129 and i got lost.

Answer = The square root of the adjacent side of the 90 degree triangle, multiplied by the breadth of Covert's eyebrow, minus the number of pubes stuck to MCD's chin, divided by x

Is it 96?

Or 29?

(N^2+2N+1)+(2n^2+n+2) = 43 * 3, so N^2+N-42= 0, whence n=6

Hence 111 means (36 +6 +1) ie., 43 in scale 10,
And 11 means (6+1), ie., 7 in 10 scale

So we have the required total as 93 in scale-10 notation.
But 93 = 2*6^2+3*6+3, which in scale 6 notation would be written as 233

Hence we would answerthe question as : "two three three" Ofcourse denary scale words, such as twenty, hundred etc., cannot be used when working in a non-denary scale notation.